264-(x^2)+x=0

Solution for 264-(x^2)+x=0 equation:

264-(x^2)+x=0

We add all the numbers together, and all the variables

-1x^2+x+264=0

a = -1; b = 1; c = +264;
Δ = b2-4ac
Δ = 12-4·(-1)·264
Δ = 1057
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(1)-\sqrt{1057}}{2*-1}=\frac{-1-\sqrt{1057}}{-2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(1)+\sqrt{1057}}{2*-1}=\frac{-1+\sqrt{1057}}{-2}
$